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Half-Life Calculator

Work out half-life problems in any direction: how much is left after a given time, how much there was to start with, how long a decay takes, or what the half-life is. Enter amounts in any unit and times in seconds through years; the answer also shows the number of half-lives elapsed and the mean lifetime.

Quick examples

Any unit — grams, mg, atoms, becquerels — as long as both amounts use the same one.

Carbon-14: 5,730 years. Iodine-131: 8.02 days.

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Answer88.61 (88.61% of the start)
Amount remaining
88.6062
Initial amount
100
Share remaining
88.6062%
Half-lives elapsed
0.1745
Time elapsed
1,000 yr
Half-life
5,730 yr
Mean lifetime (τ = T ÷ ln 2)
8,266.64 yr

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      Formula

      Amount remaining: N = N₀ × (½)^(t ÷ T)
      Initial amount: N₀ = N × 2^(t ÷ T)
      Time elapsed: t = T × log₂(N₀ ÷ N)
      Half-life: T = t ÷ log₂(N₀ ÷ N)
      Decay constant: λ = ln 2 ÷ T; mean lifetime: τ = T ÷ ln 2 ≈ 1.4427 × T

      How to use it

      1. Choose what to solve for.
      2. Enter the amounts in the same unit, whatever it is — grams, milligrams, atoms or becquerels.
      3. Enter the times, choosing a unit for each; they do not need to match.
      4. Read the answer and the number of half-lives; check it against the table of halvings below.

      Worked examples

      100 g of carbon-14 after 1,000 years: N = 100 × (½)^(1,000 ÷ 5,730)

      Answer
      88.61 (88.61% of the start)
      Amount remaining
      88.6062
      Half-lives elapsed
      0.1745
      Mean lifetime (τ = T ÷ ln 2)
      8,266.64 yr

      How long until carbon-14 falls from 100 to 25? log₂(100 ÷ 25) = 2 half-lives

      Answer
      11,460 years
      Time elapsed
      11,460 yr
      Half-lives elapsed
      2
      Share remaining
      25%

      50 mCi of iodine-131 (half-life 8.02 days) after 20 days

      Answer
      8.877 (17.75% of the start)
      Amount remaining
      8.8771

      80 g decays to 10 g in 24 hours — three halvings, so the half-life is 8 hours

      Answer
      8 hours
      Half-life
      0.0009126 yr
      Half-lives elapsed
      3

      Initial amount if 12.5 g is left after 17,190 years of carbon-14 decay (3 half-lives)

      Answer
      100
      Initial amount
      100

      200 mg of caffeine after 12 hours, with a 5-hour half-life

      Answer
      37.89 (18.95% of the start)
      Amount remaining
      37.8929

      Halvings at a glance

      After 1 half-life 50% remains, after 2 25%, after 3 12.5%, after 4 6.25%, after 5 3.125%, after 7 about 0.78% and after 10 about 0.098%. If the time is a whole number of half-lives you can check the answer in your head.

      Common half-lives

      Carbon-14: 5,730 years, the value used in most textbook dating problems. Published radiocarbon ages are still quoted on the older Libby half-life of 5,568 years by convention and then calibrated, so lab dates differ from this simple calculation. Iodine-131: 8.02 days. Uranium-238: about 4.47 billion years.

      The idea applies beyond radioactivity: the body clears many drugs with a roughly constant half-life. Caffeine’s is commonly quoted at around 5 hours, though it varies widely between people.

      Questions people ask

      How do you calculate half-life?

      Divide the elapsed time by log₂ of the starting amount over the amount left. 80 g falling to 10 g in 24 hours: log₂(8) = 3, so T = 24 ÷ 3 = 8 hours.

      How much carbon-14 is left after 1,000 years?

      88.61% of it: 100 × (½)^(1,000 ÷ 5,730) = 88.61.

      How long does it take for 75% of a sample to decay?

      Two half-lives, because 25% remains. For carbon-14 that is 11,460 years.

      What is the difference between half-life and mean lifetime?

      The half-life is the time for half to decay. The mean lifetime, the average time an atom survives, is longer by a factor of 1/ln 2 ≈ 1.443: 8,267 years for carbon-14.

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