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Acceleration Calculator

Find acceleration from a change in velocity over time, or rearrange the same equation to solve for final velocity, initial velocity or time. A separate mode uses Newton’s second law to get acceleration from force and mass. Units are selectable, and the result is also given in g and ft/s² with the distance covered.

Quick examples
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Answer4 m/s² (0.4079 g)
Acceleration
4 m/s²
In g (9.80665 m/s²)
0.4079 g
In feet per second squared
13.1234 ft/s²
Final velocity
20 m/s
Initial velocity
0 m/s
Time
5 s
Distance covered
50 m

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      Formula

      Acceleration: a = (v − v₀) ÷ t
      Final velocity: v = v₀ + a × t
      Initial velocity: v₀ = v − a × t
      Time: t = (v − v₀) ÷ a
      Newton’s second law: a = F ÷ m (1 N = 1 kg·m/s²)
      Distance under constant acceleration: d = (v₀ + v) ÷ 2 × t

      How to use it

      1. Choose the unknown.
      2. Enter the other values, choosing units for velocities, time and mass.
      3. Use a negative acceleration for an object that is slowing down.
      4. Read the answer in m/s² (or m/s or s), with g and ft/s² underneath.

      Worked examples

      From rest to 20 m/s in 5 s: a = (20 − 0) ÷ 5

      Answer
      4 m/s² (0.4079 g)
      Acceleration
      4 m/s²
      In g (9.80665 m/s²)
      0.4079 g
      In feet per second squared
      13.1234 ft/s²
      Distance covered
      50 m

      A car doing 0–60 mph in 8 s: 26.8224 m/s ÷ 8 s

      Answer
      3.353 m/s² (0.3419 g)
      Acceleration
      3.3528 m/s²
      Distance covered
      107.29 m

      Final velocity from 10 m/s, accelerating at 2 m/s² for 3 s: v = 10 + 2 × 3

      Answer
      16 m/s (35.79 mph)
      Final velocity
      16 m/s
      Distance covered
      39 m

      Initial velocity if you reach 25 m/s after 5 s at 3 m/s²: v₀ = 25 − 3 × 5

      Answer
      10 m/s (22.37 mph)
      Initial velocity
      10 m/s

      Time to stop from 30 m/s braking at −6 m/s²: t = (0 − 30) ÷ −6

      Answer
      5 s
      Time
      5 s
      Distance covered
      75 m

      Newton’s second law: 3,000 N pushing 1,200 kg, a = 3,000 ÷ 1,200

      Answer
      2.5 m/s² (0.2549 g)
      Acceleration
      2.5 m/s²

      Reference values

      Standard gravity, 1 g, is 9.80665 m/s² (about 32.17 ft/s²); 9.81 or 9.8 is used in most homework. A car going 0–60 mph in 8 seconds averages 3.35 m/s², about a third of a g.

      Deceleration is just negative acceleration: braking from 30 m/s to a stop in 5 s is (0 − 30) ÷ 5 = −6 m/s².

      Units and signs

      Acceleration is velocity per unit of time, so its SI unit is meters per second per second (m/s²). Convert km/h or mph to m/s before dividing, or the answer will be in a mixed unit such as mph per second. Keep one direction positive throughout a problem; a sign flip mid-way is the usual source of a wrong answer.

      Questions people ask

      How do you calculate acceleration?

      Subtract the initial velocity from the final velocity and divide by the time. From rest to 20 m/s in 5 s: (20 − 0) ÷ 5 = 4 m/s².

      How do you find acceleration from force and mass?

      Divide the net force by the mass: a = F ÷ m. 3,000 N on a 1,200 kg car gives 2.5 m/s².

      What is the acceleration of a car that goes 0 to 60 mph in 8 seconds?

      60 mph is 26.82 m/s, so a = 26.82 ÷ 8 = 3.35 m/s², or 0.34 g. It covers about 107 m doing it.

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